# Conjugate of an integral

1. Jun 28, 2006

### gonzo

In the complex conjugate of an integral equal to the integral of the complex conjugate?

If so, is there an easy way to show this?

Thanks.

2. Jun 28, 2006

### matt grime

In general, the answer is no. Just consider analytic functions integrated round loops and apply Morera's Theorem (if the integral of a function round all closed paths is zero then the function is analytic).

3. Jun 28, 2006

### gonzo

Well, what about when you look at the inner product defined for L2 space. Here the claim is made that:

$$<f,g> = \int f\overline{g}$$

$$<f,g> = \overline{<g,f>}$$

$$\int f\overline{g}=\overline{\int g\overline{f}}$$

But this is the same as saying in this case that the conjugate of the integral is the integral of the conjugate. How is this supported if this isn't true in general?

Last edited: Jun 28, 2006