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## Homework Statement

Two bodies A and B of equal mass m, connected by a light inextensible string, are placed on a smooth horizontal table with the string just taut. A is projected with velocity U at 45 degrees to the direction AB. Determine the impuslive tension in the string when it becomes taut.

## Homework Equations

## The Attempt at a Solution

Well, following from previous examples i tried to find the momentum in direction AB and perpendicular to AB.

Momentum in direction AB

mu + mu = U cos45

2mu = Ucos45

u = (Ucos45) / 2m

Momentum perpendicular to AB

mv = U sin45

v = (Usin45)/m

Impulsive Energy at A

T = mu

= (Ucos45)/2

= (U * 1/root2)/2

I think i've gotten it wrong. answer should be 1/4 m U root 2. can anyone help me out? I don't know if it's an algebra problem or (most likley) a method problem.