Can someone please help me with the following problem: A solid cube of wood of side 2a and mass M is resting on a horizontal surface. The cube is constrained to rotate about an axis AB. A bullet of mass m and speed v is shot at the face opposite ABCD at a height of 4a/3. The bullet becoes embedded in the cube. Find the minimum value of v required to tip the cube so that it falls on face ABCD. Assume m<<M. This is what I got so far: I understand that it is a perfectly inelastic collision and that mv=(m+M)V L(initial)=I*Omega where I is the combined Inertia for both object. The I for a cube rotating around one of its edge is I=(8Ma^2)/3 and the bullet is a point mass with an r of sgrt((4a/3)^2+(2a)^2). omega=V/R where V is the final speed and R is the radius of rotation, which is ....???? Thank you in advance!