An atomic nucleus initially moving at 500 m/s emits an alpha particle in the direction of its velocity, and the new nucleus slows to 480 m/s. If the alpha particle has a mass of 4.0 u and the original nucleus has a mass of 226 u, what speed does the alpha particle have when it is emitted? Well this is what I came up with so far: m1=226 V1=500 V1'=? m2=4 V2=? V2'=480 Use Conservation of Momentum and conservation of kinetic energy to get these equations, respectively: 226(500) + 4(V2) = 226(V1') + 4(480) and... .5(226)(500)^2 + .5(4)(V2)^2 = .5(226)(V1')^2 + .5(4)(480)^2 Hopefully this is correct so far....now I know I'm supposed to do substitution next, but I'm having some algebra problems. I got V2= -2.77e4 + 56.5(V1') I'm not sure if this is correct I'm ashamed to say it, but I'm having alot of trouble doing the algebra after I substitute it into the other equation.