1. The problem statement, all variables and given/known data A bungee jumper of mass 64.5 kg (including safety gear) is standing on a platform 48.0 m above a river. The length of the unstretched bungee cord is 10.1 m. The force constant of the cord is 65.5 N/m. The jumper falls from rest and just touches the water at a speed of zero. The cord acts like an ideal spring. Use conservation of energy to determine the jumper’s speed at a height of 12.5 m above the water on the first fall. 3. The attempt at a solution so I decided that Eg(at the top of the platform)=Ek+Ee+Eg'(12.5 above water floor) so for h initial i used 48m...h'= 12.5m and x(stretch of the cord)= 25.5m therefore mg(48)=.5k(25.5^2)+.5mv^2+mg(12.5) i solved for V and got 5.96m/s, the answer is 6.37m/s...please help!!