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A .40 kg ball is thrown with a speed of 12m/s at an angle of 33 degrees. a) what is its speed at its highest point, and b) how high does it go? (Use conservat ionfo energy and ignore air resistance)

I think I'm supposed to use the formula .5mvi^2 + mgy1 = .5mvf^2+mgy2 .

How do I find the speed at the highest point? m=.4, and vi=12 right? Please help!

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# Homework Help: Conservation of Energy Problem.

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