1. A 70kg pole vaulter runs with a top speed of 9.5 m/s. During the jump the pole is highly curved then straigtens out. The vaulter is able to clear a bar height of 5.4m a) Using conservation of energy, determine the maximum height the vaulter should be able to clear. The vaulters center of gravity point is 90cm above his feet. b) Discuss the energy conversions that take place. 2. K=.5mv^2, Ug=mgh 3. (a) .5mv^2=mgh. I got h is equal to 4.9m but I added the center of gravity point to make it 5.8 m. Is this right? why do we add the COG point? (b) Kinetic energy transforms to energy into the bending the pole, the pole then converts the energy into gravitational potential energy by raising you a height H. Thanks!!!