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Conservation of energy

  1. Mar 16, 2012 #1
    I attached the problem.

    The solution is of the form:
    .5*(5/32.2)v^2+.5(10/32.2)(12/18*v)^2 + 5*18/12*sin(60)-10*12/12*sin60=0

    I don't understand why they put the radius in the kinetic energies like the 12/18 part. I know you have to do that, but I don't understand why.
     

    Attached Files:

  2. jcsd
  3. Mar 16, 2012 #2
    Hey Pyroknife,

    Please submit your approach to the solution first.
     
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