Calculating Velocity at the Bottom of a Quarter Circle Track

In summary, the conversation is discussing the calculation of the velocity of a block at the bottom of a frictionless track, given its initial downward velocity and the track's radius. The conversation includes a discussion of the equations for translational and rotational kinetic energy, gravitational potential energy, and the moment of inertia. Ultimately, it is determined that the velocity at the bottom of the track can be calculated using the equation vf2=vi2+ghinitial, and that the radius of the track is equal to the initial height of the block.
  • #1
tennisgirl92
43
1

Homework Statement


A block of mass 10kg starts at the top of a frictionless track which forms a quarter circle with radius 10m. It is given an initial downward velocity of 10m/s. What is the velocity at the bottom of the track?

Homework Equations


KEtranslational, f+ KErotational, f+PEf=KEtranslational, i+KErotational, i+ PEf
KE, rotational=1/2Iw2
KE, translational=1/2mv2
PE=mgh
I=MR2
w=v/r

The Attempt at a Solution


I believe the initial equation would be set up like this.
1/2mvf2+ 1/2 MR2(V/R)2+mghf=1/2mvi2+1/2 MR2(V/R)2+mghi

which would then reduce to:
vf2=vi2+ghinitial

This does not seem like the likely way to do it because we are not given the height of the mass at the top. Should I be using the rotational and translational KE in the equation? At what point is it rotational and what point translational?
 
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  • #2
tennisgirl92 said:
vf2=vi2+ghinitial

This does not seem like the likely way to do it because we are not given the height of the mass at the top.

Look carefully.

tennisgirl92 said:
Should I be using the rotational and translational KE in the equation? At what point is it rotational and what point translational?

Why would it rotate? When does something rotate?
 
  • #3
Mastermind01 said:
Look carefully.Why would it rotate? When does something rotate?

Would the radius be the initial height?

When it is rolling? I'm not exactly sure.
 
  • #4
tennisgirl92 said:
Would the radius be the initial height?

That is correct.

tennisgirl92 said:
When it is rolling? I'm not exactly sure.

Try and think intuitively if you don't know the physics behind it.
 
  • #5
Mastermind01 said:
That is correct.
Try and think intuitively if you don't know the physics behind it.
Ok, now I see how to do this. I obtained 17.2 m/s, which is correct. Thank you!

However, I still don't see how the radius could be equal to the height of the ramp. There is a picture provided that looks like a skateboard ramp, with a strict vertical height and then the inside being curved with a radius. The vertical height does not look equal to the radius, even though I know this is not to scale.
 
  • #6
Does the picture below look like the picture you have of the skateboard ramp? Is the quarter circle oriented like that?
Quarter circle track.jpg
 
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  • #7
TomHart said:
Does the picture below look like the picture you have of the skateboard ramp? Is the quarter circle oriented like that?View attachment 197493
yes, it is just like that, except flipped so that the curve is on the right and height on the left.
 
  • #8
So does it make sense to you that the radius = height?
 
  • #9
Yes, I do see it now-my picture did not have the radius being pointed horizontally and vertically, just down the middle. Thank you for all your help!
 
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1. What is the law of conservation of energy?

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