- #1

carl fischbach

in instance cited below?

You place a particle at the origin on a x-y axis

and accelerate it to 61% of c in the y direction.

Then you accelerate it to 61% of c in the x direction.

The net velocity of the particle will be

86% of c at 45 degrees.The key here is that it

takes approximately 3 times the energy to

accelerate the particle in the x direction than

the y direction, due to the fact that the net

velocity change in the y direction is 0%-61% of c

and in x direction the net velocity change is

61%-86% of c.If the rate of acceleration,distance

of acceleration and time of acceleration are the

same on the x and y axis, then force of acceleration on

the x axis has to be greater than

on the y axis, since the energy of acceleration

on the x axis is 3 times that of the y axis.

Therefore the momentum on the x axis is greater

the y axis.

If the particle's final velocity is 86% of c at

45 degrees then the momentum of acceleration

should be equal on both the x and y axis.

Is there a discrepancy in momentum here?