1. The problem statement, all variables and given/known data (2) A fuel tank with a total mass of 6 kg is moving with a speed of vi = 0.5 m/s when it explodes into three pieces. The three pieces fly away from the explosion in the directions shown in the figure; N.B., vi and v3 point in the same direction. The masses of the pieces are: m1 = 1 kg, m2 = 2 kg and m3 = 3 kg. What is the speed (in m/s) of the m1 piece if v3 = 6 m/s? v1 and v2 point in negative x direction(left). v1 points positive Y(up) and v2 points negative Y θ1 between v3 and v1 = 127 degrees θ2 between v1 and v2 = 90 θ3 between v3 and v2 = 143 2. Relevant equations Pf = Pi 3. The attempt at a solution I set Pi and v3 to be on the x axis moving right as positive. There is no Piy Pix = 6 kg * .5 m/s = 3 kg m/s Piy = 0 Pfx = 3 kg m/s = 3 kg * 6 m/s - m1v1sinθ - m2v2sinθ Pfy = 0 = m1v1cosθ - m2v2cosθ If I can get one of the remaining velocities I'm home free. I tried getting the hypotenuse using tan X/6 = 127 and got x to = 536.7...or some such nonsense.