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Conservation of Momentum

  1. Sep 5, 2005 #1
    I have been working on this for some time, maybe I'm just using the wrong formula.

    A 120 kg tackler traveling 3 m/sec tackles a 75 kg halfback running 6m/sec in the opposite direction. What is their common speed immediately after the collison?

    Thank you.
  2. jcsd
  3. Sep 5, 2005 #2
    Use the formula

    (M1 x U1) + (M2 + U2) = (M1 x V1) + (M2 x V2), Conservation of momentum forumla.

    where M1 = Tackler Mass
    M2 = Halfback Mass
    U1 = Tackler Speed
    U2 = Halfback speed
    V1 = V2 (since the speed after colision is common) = Speed of both of them after the collision.
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