A particle of rest mass Ma, decays into two massles particles of B abd C of energy Eb and Ec respecitvely. The momenta of particles B and C are separated by an angle [tex]\theta[/tex]. Calculate the combinded momentum and combined energy of B and C and hence show that particle A has a mass given by,(adsbygoogle = window.adsbygoogle || []).push({});

Ma = 1/[tex]c^2[/tex] . [sqrt(2EbEc(1- cos [tex]\theta[/tex])]

Pa = 0 = Pb + Pc = [tex]\gamma[/tex]MbVb + [tex]\gamma[/tex]McVc

E = Ea = Eb + Ec

= [tex]\gamma[/tex]Ma[tex]c^2[/tex]

I know that Eb and Ec can be easily found using the [tex]E^2[/tex] formula, but am not sure how to take the equations and find Ma.

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# Conservations laws relativity

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