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Conservative force

  1. Nov 11, 2004 #1
    a single conservative force f(x) acts on a 1.0 kg particles that move along the x axis. the potential energy u(x) associated with f(x) is given by u(x)=-4xe^(-x/4) J, where x is in meters. at x=5.0 m, the particles has a kinetic energy of 2.0J. a) what is the mechanical energy of the system? determine the equation for fx as a function of xfor what x(finite)value of x does fx=0

    Emech=K+U
    I plugged x=5 into u(x) = -5.73
    therefore Emech=2+(-5.73)=-3.73 J Is it right?
    for the second one Fx= - du/dx so I come up with fx= (4-x)e^(-x/4)
    and I stuck . COuld you guy give me a hint thank you
     
    Last edited: Nov 11, 2004
  2. jcsd
  3. Nov 11, 2004 #2
    I'm not sure about the notation, what is the difference between Fx and fx?
    About your calculations, they look ok to me. And about the last question, I don't understand your problem. This one is easier than the others, so maybe you can elaborate on what the problem is.
     
  4. Nov 11, 2004 #3
    I am sorry for the typo fx and Fx is the same, for the second part : x=4 so the fx=0???
     
    Last edited: Nov 11, 2004
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