- #1
Bennyboymalon
- 3
- 0
We are told that the force field F=([tex]\mu[/tex]z + y -x)i + (x-[tex]\lambda[/tex]z)j + (z+([tex]\lambda[/tex]-2)y - [tex]\mu[/tex]x)k
Having already calculated in the previous parts of the question
1:the line integral (F.dx) along the straight line from (0,0,0) to (1,1,1)
2:the line integral (F.dx) along the path x(t)=(t,t,t^2) from (0,0,0) to (1,1,1)
returning the answers
1: 0
2: ([tex]\lambda[/tex] - [tex]\mu[/tex] - 1)/3
The final part of the question (which I need help on please!) asks to calculate values for [tex]\mu[/tex] and [tex]\lambda[/tex] for which F is conservative.
I know that F.dx =0 for a conservative field and that the value of the line integral is path independant. Can therefore equate the answer of part 2 to zero, thus returning;
[tex]\lambda[/tex] = 1 + [tex]\mu[/tex] and/or [tex]\mu[/tex] = [tex]\lambda[/tex] - 1
but then how is this useful?
Could use curl F = 0 but curl is a vector and so not useful in returning scalar values for the two constants.
Could calculate an expression for f (x,y,z) as gradf=F but i have tried this and it gets pretty complicated and of course don't have any numerical value to equate this to, so that subbing in expressions for the constants could help return a value for each. I'm going to keep trying it but any hints on how to solve this problem would be much appreciated!
many thanks
Having already calculated in the previous parts of the question
1:the line integral (F.dx) along the straight line from (0,0,0) to (1,1,1)
2:the line integral (F.dx) along the path x(t)=(t,t,t^2) from (0,0,0) to (1,1,1)
returning the answers
1: 0
2: ([tex]\lambda[/tex] - [tex]\mu[/tex] - 1)/3
The final part of the question (which I need help on please!) asks to calculate values for [tex]\mu[/tex] and [tex]\lambda[/tex] for which F is conservative.
I know that F.dx =0 for a conservative field and that the value of the line integral is path independant. Can therefore equate the answer of part 2 to zero, thus returning;
[tex]\lambda[/tex] = 1 + [tex]\mu[/tex] and/or [tex]\mu[/tex] = [tex]\lambda[/tex] - 1
but then how is this useful?
Could use curl F = 0 but curl is a vector and so not useful in returning scalar values for the two constants.
Could calculate an expression for f (x,y,z) as gradf=F but i have tried this and it gets pretty complicated and of course don't have any numerical value to equate this to, so that subbing in expressions for the constants could help return a value for each. I'm going to keep trying it but any hints on how to solve this problem would be much appreciated!
many thanks