- #1
pallab
- 36
- 3
Homework Statement
Consider the potential field V(x, y) which is 0 and -Vo (V0 > 0) respectively in the regions
of y greater and less than zero . Let θ and θ' be the angles of incidence and refraction of
the particle with the y-axis at the point of incidence as it crosses the x-axis . The ratio
sin(θ) / sin(θ ') is given (in terms of Δ = Vo / E) by
region1
(a)√(1+2Vο/E)
(b)√(1+Vο/E)
(c)1+Vο/E
(d)1+2Vο/E
Homework Equations
nsinθ=n'sinθ'
sinθ/sinθ'=v/v'[where v=velocity of particle in 1 & v'in 2]
The Attempt at a Solution
1/2mv2=E=1/2mv'2-Vο
1/2mv'2-1/2mv2=Vο
(v'2 -v2)/v2=2Vο/mv2
(v'2 /v2 )-1=Vο/(1/2mv2)
∴sinθ'/sinθ=√(1+Vο/E)
Which is similar to option b but in question it is sinθ/sinθ'
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