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Considering E=MC2

  1. Oct 17, 2008 #1
    By analyzing E=MC2 dimensionally, we will get these results.

    kgM/S2 = kg(M2/S2)
    = kg(m)(m/s2)
    = kgm/s2(m)
    = E x distance

    E != Es where E = energy and s = distance or displacement. What we are seeing here with Einstein's relativity is that energy has a factor of distance or space as well. Is this wrong or can soeone correct me on this, please?

    Es is no longer energy but something else and should be treated as such, I believe.
     
  2. jcsd
  3. Oct 17, 2008 #2

    Integral

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    [tex] kg\frac { m} {s^2} [/tex] = Mass x acceleration is the units of Force, not energy. Energy is [tex] kg\frac { m^2} {s^2} [/tex] just like in [tex] E = m c^2 [/tex]
     
  4. Oct 17, 2008 #3
    Thanks for the correction.
     
  5. Oct 18, 2008 #4

    HallsofIvy

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    Of course, mc2 has the same units as (1/2)mv2, the kinetic energy.
     
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