(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A mouse leaves a hole in the baseboard and runs along the wall in a straight line towards a

cupboard where cookies are stored, 12 meters from the hole. The mouse starts at rest and

maintains a constant acceleration of 0.1m/s2 before reaching top speed of 1 m/s, which it

maintains for the rest of the journey. When the mouse is 3 meters from the cookie

cupboard, a cat turns the corner and enters the kitchen, moving at 0.5 m/s. It immediately

begins to chases the mouse. The point where the cat enters is 14 meters from the cookie

cupboard.

2. Relevant equations

a) Where is the mouse located when it reaches top speed?

b) If the cat catches the mouse just as it reaches the cookie cupboard, what minimum

constant acceleration must the cat maintain?

c) How fast is the cat moving when it catches the mouse?

d) How much time has passed since the mouse left the hole?

3. The attempt at a solution

I found A by using Vf^2=V0^2+2a(Change in X)

I am stuck on B

I know first I need to know how long it takes for the mouse to reach the cupboard but i am confused on which formula to use. I know its 2 different equation one for before it reachs top speed when the acceleration is non constant, and one for when it is constent.

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# Homework Help: Constant acceleration question

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