A rock is thrown vertically upward from ground level at time t = 0. At t = 1.6 s it passes the top of a tall tower, and 2.0 s later it reaches its maximum height. What is the height of the tower? My thought process: First find initial velocity: v=vo+at 0=vo+(-9.8)(2) vo=19.6 m/s Then you can find the height of the tower, where x-xo is the displacement/height of the tower: x-xo=vo*t+.5*a*t^2 x-xo=19.6*1.6+.5*-9.8*1.6^2 x-xo=18.816 m However, WileyPlus says that I am wrong. What am I doing wrong?