Constant Electric Field

  • Thread starter Kernul
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  • #26
SammyS
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You're right. I switched the signs. I was doing it in mind without writing.

So I should add ##\frac{1}{4 \pi \epsilon_0} \frac{q}{c^2}## to ##\frac{q}{4 \pi \epsilon_0} \left( \frac{1}{r_1^2} - \frac{1}{c^2} \right)##?
What will that give as a result ?
 
  • #27
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##\frac{1}{4 \pi \epsilon_0} \frac{q}{r_1^2}##
Oh! Now I got it! Thanks so much!
 

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