- #26

SammyS

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What will that give as a result ?You're right. I switched the signs. I was doing it in mind without writing.

So I should add ##\frac{1}{4 \pi \epsilon_0} \frac{q}{c^2}## to ##\frac{q}{4 \pi \epsilon_0} \left( \frac{1}{r_1^2} - \frac{1}{c^2} \right)##?