# Constant Force

1. Sep 18, 2007

### chaotixmonjuish

A block of mass 8.3 kg is pulled along a horizontal frictionless floor by a cord that exerts a force of 53.0 N at an angle 25.3° above the horizontal. What is the magnitude of the acceleration of the block?

I'm just wondering how I set up an equation with an angle.

2. Sep 18, 2007

### bel

Separate the applied force into its horizontal and vertical components using the trigonometric ratios or use the method of tension co-efficients.

3. Sep 18, 2007

### chaotixmonjuish

That's where I'm having a problem.

would it be something like:

y=(mass)(sin(30)a)
x=(mass)(cos(30)a)

4. Sep 18, 2007

### bel

How about $$F_x = F(cos (\frac{\pi}{6}))$$ ?

5. Sep 18, 2007

### chaotixmonjuish

wow, how did you get that

6. Sep 18, 2007

### HallsofIvy

Staff Emeritus
Yes, something like that. But of course the angle isn't 30 degrees.