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Homework Help: Constant Force

  1. Sep 18, 2007 #1
    A block of mass 8.3 kg is pulled along a horizontal frictionless floor by a cord that exerts a force of 53.0 N at an angle 25.3° above the horizontal. What is the magnitude of the acceleration of the block?

    I'm just wondering how I set up an equation with an angle.
     
  2. jcsd
  3. Sep 18, 2007 #2

    bel

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    Separate the applied force into its horizontal and vertical components using the trigonometric ratios or use the method of tension co-efficients.
     
  4. Sep 18, 2007 #3
    That's where I'm having a problem.

    would it be something like:

    y=(mass)(sin(30)a)
    x=(mass)(cos(30)a)
     
  5. Sep 18, 2007 #4

    bel

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    How about [tex]F_x = F(cos (\frac{\pi}{6})) [/tex] ?
     
  6. Sep 18, 2007 #5
    wow, how did you get that
     
  7. Sep 18, 2007 #6

    HallsofIvy

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    Science Advisor

    Yes, something like that. But of course the angle isn't 30 degrees.
     
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