# Homework Help: Constant in OHMs law

1. Jul 31, 2011

### bambilmiller

1. Write the equation for each run in the form (potential=constant x current)
{the form has two numerical list to work with}

2. How do I find the constant from these 2 lists? Is it the correlation that the question is looking for? or, Is it OHMs constant, that the question is talking about??

2. Jul 31, 2011

### kuruman

Hi bambilmiller and welcome to PF.

If I asked you to state Ohm's Law, what would you say?

3. Jul 31, 2011

### bambilmiller

It is the relationship among voltage, current and resistance. Where the current in a circuit is directly proportional to teh voltage established across teh circuit and is inversly proportional to the resistance of the circuit. I=V/R

4. Aug 1, 2011

### kuruman

Correct. Now can you answer question 1 and write the equation?
For question 2, look at your list. It has two columns of numbers. What are the symbols corresponding to the numbers that you know? Can you find an equation expressing the symbol that you don't know in terms of the symbols that you do know? If so, can you plug in numbers to find the unknown in terms of the known quantities for each line of your list?

5. Aug 1, 2011

### bambilmiller

That still does not answer my question. What is the constant? How do I figure out what it is?

6. Aug 1, 2011

### kuruman

I told you how to figure it out. If you answer my questions first (there are three of them, please answer them in order), you will be led to the answer of your question.

7. Aug 1, 2011

### PeterO

You could draw a graph for each table and see if you get a straight line. If so you might be able to see it is the same as y = 5x or y= 10x graph, or similar.

8. Aug 1, 2011

### bambilmiller

Is the correct equation for the first part V=IR ????

9. Aug 1, 2011

### SammyS

Staff Emeritus
Solve V=IR for R.

10. Aug 1, 2011

### bambilmiller

Thank you everyone for all your help. The light bulb just went off!!! :)

11. Aug 1, 2011

### SammyS

Staff Emeritus
Or on ???

12. Aug 1, 2011

### bambilmiller

Either way, it's all good!