(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Object A of mass m is pushed with a constant force, another object B of the same mass is pushed with a force that does work at constant rate. Velocity of both objects increase from v to 2v and they move a distance of s. Find the ratio of the time taken by objects A and B to move the distance s

2. Relevant equations

3. The attempt at a solution

Firstly, for object A

s = 1/2(v + 2v)t

t = 2s/3v

Object B has constant power, so

change in energy = work done = 3/2 mv^{2}

3/2 mv^{2}= Pt

v = (2Pt/3m)^{1/2}

integrating this term, i get

s = 1/3 (8Pt^{3}/9m)^{1/2}

But how do i eliminate m and p?

**Physics Forums | Science Articles, Homework Help, Discussion**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Homework Help: Constant power problem

**Physics Forums | Science Articles, Homework Help, Discussion**