How Do You Calculate the Mass of Silver Using Constant Pressure Calorimetry?

[Bulc9408]

PRoblem statement-
The specific heat of silver is 0.235J/gC and the specific heat of water is 4.184J/gC. A piece of silver at 94.31C was dropped into a constant pressure calorimeter containing 148g of water at 24.08C. The final temperature of the water and silver was 25.39C. Assuming that the calorimeter itself absorbs a negligible amount of heat, whatw as the mass of the silver?

This is the problem at hand, and I am on the tail end of a large study period and have finished a worksheet minus this particular problem. I would appreciate the help. Thanks.
I just don't not understand what equations to use/ how to modifythem
q=m.s.(change in temp). q=C(change in temp)?

 

[Borek]

heat lost by silver = heat gained by water

heat = mass x specific heat x change in temperature

It leads to one simple equation that you have to solve for silver mass.

 

[Blueshift5]

I understand your struggle and am here to help. The problem statement provided involves using constant pressure calorimetry to determine the mass of a piece of silver. To solve this problem, we can use the following equation:

q = mCΔT

Where q is the heat absorbed or released, m is the mass, C is the specific heat, and ΔT is the change in temperature.

In this case, the silver is initially at a temperature of 94.31°C and the water is at 24.08°C. When they reach thermal equilibrium, the final temperature is 25.39°C. Using the equation above, we can set up the following equation:

qsilver + qwater = 0

Since the heat lost by the silver is equal to the heat gained by the water. Substituting in the values for specific heat and temperature difference, we get:

mSilver x 0.235 x (94.31-25.39) + 148 x 4.184 x (25.39-24.08) = 0

Solving for mSilver, we get a mass of 3.18 grams. This means that the mass of the silver dropped into the calorimeter was 3.18 grams.

I hope this helps you understand how to approach this type of problem using constant pressure calorimetry. Remember to always set up the equation using the conservation of energy principle and solve for the unknown variable. Best of luck with your studies!