Calculating Constant Thrust for Jet-Powered Drag Car in Vehicle Dynamics Class

In summary, the student is trying to solve for the thrust in a car accelerating from 0 to 260 mph. The air density and the acceleration are not constant, so the student has to solve the differential equation. The thrust is constant by definition, and the student has to determine the value of T given that vo = 0, vf = 260 mph, and sf-so = 1320 ft.
  • #1
dochalladay32
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I'm a math guy taking engineering classes more or less for fun, so some of the stuff I should know I probably missed in a basic dynamics class. I feel really dumb that I can't figure this out.

I'm in a vehicle dynamics class and I have to calculate the constant thrust T for the following situation:

I have a jet-powered drag car that weighs 3220 lbs and goes from 0 to 260 mph in a quarter mile. The drag force is D = 0.006*v^2, D is in lbs and v is in ft/s. We are to neglect the tire rolling resistance so only T and D affect the movement of the car. We are also told to use 0.002378 slug/ft^3 for air density. For some reason, I have no clue how to calculate the thrust in this case. I'm used to mass flow rates and exhaust velocities.

What am I missing that presumably makes this problem so easy? Thanks for anything you guys can offer.
 
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  • #2
I am not sure why you were given the air density since it is already factored into your formula for D (assuming it is given correctly).

The acceleration is not constant since the drag force is not constant. You have to solve the differential equation formulated from Newton's 2nd law, where a = dv/dt or a = d^2x/dt^2. Unless your good at calculus, the solution is a bit messy. Being a math guy, I'm sure you can solve it better than I. What does Newton 2 tell you about the equation to use to solve for the Thrust?
 
  • #3
The air density threw me off as well, because there is no way to get A_f and C_d, so it's rather pointless here. That's why I was thinking there had to be some trick to what he was asking, because it looks excessive.

What you mentioned was what I was trying to do, but he seems to think that we should be able to find the value of T rather easily, and I'm just not seeing that. Thanks for confirming what I had in mind and I'll just go with it and maybe it'll come in class next week.

I am solving the differential equation T - 0.006v^2 = 100*dv/dt for v with initial velocity of 0. That will give me motion curves I need, which is another part of the homework. I'll take it from here and hopefully this will lead to an answer for T. Doesn't seem like it is going to be constant though, but it's late so maybe I just can't see it yet.

Thanks a lot!
 
  • #4
T is constant by definition. You have to determine T knowing that vo = 0, vf = 260 mph, and sf-so = 1320 ft. You DE can be solved by separation of variables or by using one of the numerical techniques for first order ODEs.
 
  • #5
Thanks for the help guys. Took some work doing the integrals, but I got answers that all make sense. Takes 5956 lbs of thrust to get the car up to that speed in a quarter mile. Everything checks out. Now I have to do it again without the drag, but the integrals will be much nicer this time. Thanks again!
 

1. What is constant thrust calculation?

Constant thrust calculation is a method used to determine the amount of force or thrust needed to keep an object moving at a constant speed. This calculation takes into account factors such as the object's mass, air resistance, and gravitational pull to determine the necessary thrust.

2. How is constant thrust calculated?

Constant thrust is calculated by using the formula F=ma, where F is the force or thrust, m is the mass of the object, and a is the acceleration. This formula can also be modified to include other factors such as air resistance and gravitational pull.

3. Why is constant thrust important?

Constant thrust is important because it allows us to accurately predict and control the movement of objects. This is particularly useful in fields such as aerospace engineering, where precise calculations of thrust are necessary for successful space missions.

4. Can constant thrust be used for any type of motion?

No, constant thrust calculations are primarily used for linear motion, where an object moves in a straight line at a constant speed. For other types of motion, such as circular or rotational motion, different calculations are needed.

5. How accurate are constant thrust calculations?

The accuracy of constant thrust calculations depends on the accuracy of the input data and the assumptions made in the calculation. In most cases, they provide a good estimate of the required thrust, but may not be 100% accurate due to external factors such as air resistance and friction.

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