1. The problem statement, all variables and given/known data Kind of wordy, please bear with me: A hare and a tortoise compete in a rase over a course 1.00 km long. The tortoise crawls straight at its maximum speed of 0.200m/s. The hare runs 8.00m/s for 0.800 km and stops to tease the tortoise. How close to the goal can the hare let the tortoise approach before resuming the race? Assume both animals move steadily at their respective speeds. 2. Relevant equations xf=1/2(Vi + Vf)*t 3. The attempt at a solution So I used the above equation. I figure, tehy have 0.200km left to go after the hare stops. So I transfer .200km to m, and plug the numbers into the above equation to find out how long it would take the rabbit to get to the finish from there. I did the same for the turtle. 200=1/2(0+8.00)*t t=50s (rabbit) 200=1/2(0+.200)*t t=2000s (turtle) So I saw it was a difference of 1950, so I decided to use the same equation to see how many meters the turtle could cover in 1950s, which would be how far the rabbit could afford to have the turtle get. xf = 1/2(0+0.200)1500s xf=195m = 0.195km Doesn't look right. Any suggestions?