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Constrained PDE : 3D -> 1D

  1. Jul 24, 2005 #1


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    I got the following PDE:

    I worked with cylindrical coordinates (r,teta,z)
    (teta is the angle between the x axis and the r vector (in xy plane))
    a,E are constants

    I got the constrains: z=0 r=a , so the whole problem is on a simple ring

    How can I make the 3D PDE just 1D in teta?
    Can I use the Laplasian in cylindrical coordinates, and throw away the d/dr and d/dz?

    I hope someone can help me.
  2. jcsd
  3. Jul 24, 2005 #2
    Without separation of variables (which I know you don't wanna do), I don't see a way.
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