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Contact Force homework

  1. Sep 27, 2006 #1
    I'm really confused about this problem -

    As shown in Figure 5-22, a force of magnitude 7.50 N pushes three boxes with masses m1 = 1.30 kg, m2 = 3.30 kg, and m3 = 5.10 kg.

    [​IMG]

    (a) Find the magnitude of the contact force between boxes 1 and 2.
    (b) Find the magnitude of the contact force between boxes 2 and 3.

    So F=7.5N. First you need to find the acceleration right? So I got a=F/m and did 7.5/(1.3+3.3) for part a. That gave me 1.63. I multiplied that with 3.3 because that's the mass of the second box and got a contact force of 5.379N but it's telling me that it's not right. If anyone could help I'd really appreciate it
     
  2. jcsd
  3. Sep 27, 2006 #2

    Doc Al

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    Staff: Mentor

    What happened to the third mass?
     
  4. Sep 27, 2006 #3
    I'm confused about how I work that in there...I was kind of doing the problem as if the third one wasn't there which is wrong. So I do 7.5/(1.3+3.3+5.1) to get a? And then once I have a how do I find the contact force?
     
  5. Sep 27, 2006 #4

    Doc Al

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    Staff: Mentor

    You apply Newton's 2nd law: First to the entire 3-block system, to find a. Then to each mass separately, to find the contact forces. (Realize that the F in F = ma is the net force.)
     
  6. Sep 28, 2006 #5
    Ahh, I figured it out, thanks
     
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