- #1
iNCREDiBLE
- 128
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Let f be that function defined by setting:
f(x) = x if x is irrational
= p sin(1/q) if x = p/q in lowest terms.
At what point is f continuous?
Continuous for irrational x, and for x = 0. Sketch:
p*sin(1/q) - p / q
= p(sin(1/q) -1/q)
But sin x - x = o(x^2) when x -> 0
So, for large q,
|p(sin(1/q) - 1/q)| < p (1/q)^2 = (p/q) / q
Is this correct?
f(x) = x if x is irrational
= p sin(1/q) if x = p/q in lowest terms.
At what point is f continuous?
Continuous for irrational x, and for x = 0. Sketch:
p*sin(1/q) - p / q
= p(sin(1/q) -1/q)
But sin x - x = o(x^2) when x -> 0
So, for large q,
|p(sin(1/q) - 1/q)| < p (1/q)^2 = (p/q) / q
Is this correct?