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Continuous functions

  1. Feb 8, 2010 #1
    1. The problem statement, all variables and given/known data

    g(x)={x+3, x[STRIKE]=[/STRIKE]3
    {2+[tex]\sqrt{k}[/tex] , x=3

    find k if g(x) is continuous
    2. Relevant equations



    3. The attempt at a solution

    I have no idea how to begin, but drawing the first part on a cartesian plane.
     
  2. jcsd
  3. Feb 8, 2010 #2
    Re: Continuity

    Are you sure g(x) is well defined? Because if it is you just have to get a k that doesn't cause a contradiction...
     
  4. Feb 8, 2010 #3
    Re: Continuity

    Hi Hallowon
    Is the first part not x+3, and x not eual to 3? YA

    To say that g(x) is continous at y=3 is to say that

    lim as x goes to 3 = f(3)

    In our case the left hand side is equal to x + 3= 3+ 3=6

    while the right hand side is equal to 2 + rootk but this must equal the left hand side for it to be continous so we have

    6= 2 + rootk
    4=rootk
    16=k

    Hope this helps. Sorry I had to give solution.haha
     
  5. Feb 8, 2010 #4
    Re: Continuity

    ahh thank you i didn't event hink to make them equal to one another. Looks like i have a long way to go for continuity -_-
     
  6. Feb 8, 2010 #5
    Re: Continuity

    Ah your welcome. Its actually not that bad. I havent really covered it but if you have any futher questions dont hesitate to ask. If you look on you tube they might have something on continuity. It would be much more helpful seeing someone go through it rather than reading from some black and white text book.
     
  7. Feb 8, 2010 #6

    Redbelly98

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    Re: Continuity

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    Giving out solutions to homework problems is against the guidelines of Physics Forums. Please review the section on Homework Help https://www.physicsforums.com/showthread.php?t=5374".
     
    Last edited by a moderator: Apr 24, 2017
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