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Continuous Random Variables

  • Thread starter Disar
  • Start date
  • #1
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I've been working on a problem and was wondering if someone could check and see if I am on the right track.

A company produces gas from two plants, A and B. (both are considered to be continuous randm variables; X and Y respectively)

For Plant A, its probability density function is:

f(x) = 0.005(x-80) for 80<x<100
0 otherwise

For plant B, it's probability denisity function is:

f(y) = 0.02(y-80) for 80<y<90

r is the octane rating of the gasoline and the gas is:

low grade if r<85
High grade if r>=85

There is an equal probability that the gas was produced at plant A or plant B.

a. What is the probabilty that today's shipment is low grade?
b. If it is low grade what is the probabiliy that it came from plant A?

Here are my answers:

a. f(x) = .0615 (for r<85)
f(y) = .25 (r<85)
The probability that it is low grade is f(x) +f(y) = .3125

b. P(A|(r<85))

P(A) = 1/2
P(r<85) = .3125

P(A|r<85) = P(A and r<85)/P(r<85) = I don't know if this is the right set up for this portion of the problem

Thanks for the help!
 

Answers and Replies

  • #2
EnumaElish
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To find low grade probability aren't you supposed to be integrating f(x) and f(y) over 0 < r < 85?
 
  • #3
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I am sorry I did not note that I performed the necessary integration for f(x) and f(y) to determine their respective values.
 
  • #4
EnumaElish
Science Advisor
Homework Helper
2,304
124
So you mistyped F(.) as f(.)? E.g. Fx(85) = [itex]\int_0^{85}f_x(x)dx[/itex] = .0615?
 

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