# Contour int.

Homework Helper
Is it just me, or i can't get the residues right...?

$$\int_{0}^{\infty} \frac{\ln^{2}z}{1+z^{2}} \ dz$$

I get $\frac{\pi^{3}}{2}$ , but the result is $$\frac{\pi^{3}}{8} [/itex]. I make a substitution $z=e^{t}$. And then convert to a contour integral closing it in the upper half-plane, where i have the poles [tex] i\frac{\pi}{2} + k\pi$$ k in N.

Daniel.

shmoe
$$\int_{-\infty}^{\infty}\frac{\log^{2}{z}}{1+z^2}dz$$