What values of p make the series converge?

In summary, the series converges for p>1 and diverges for p<=1. To determine the specific values of p for which it converges, one can use the integral test and substitute u=ln(x).
  • #1
razored
173
0

Homework Statement


Find the positive values of p for which the series converges.
[tex]\Sigma_{n=2}^{\infty} \frac{1}{n( \ln (n)^{p})} [/tex]


Homework Equations



1/n^p converges if p>1, and diverges if =<1

The Attempt at a Solution


Don't know where to begin
 
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  • #2
Try an integral test.
 
  • #3
Doesn't the integral tell me only whether it converges or diverges? I need to actually determine the values of p for which that will converge.
 
  • #4
Whether the integral converges or diverges will depend on the value of p.
 
  • #5
Is it two? Are we also assuming that p will be a positive integer rather than any positive real number?
 
  • #6
What do you get if you integrate 1/(x*(ln(x))^p)? Sure, take p to be positive. If it's not then the integral definitely diverges.
 
  • #7
http://texify.com/img/%5CLARGE%5C%21%5Cint_2%5E%7B%5Cinfty%7D%20%5Cfrac%7Bdx%7D%7Bx%20%5Cln%28x%29%5E%7Bp%7D%7D%20%3D%20%20%20%5Cleft%5B%20%5Cfrac%7B%20%5Cln%20%28%5Cln%28x%29%5E%7Bp%2B1%7D%29%7D%7B%28p%2B1%29%7D%20%5Cright%5D_2%5E%7B%5Cinfty%7D.gif
What do I do now?
 
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  • #8
Have you considered working with a Taylor approximation of ln(1 + n).
 
  • #9
e(ho0n3 said:
Have you considered working with a Taylor approximation of ln(1 + n).

That is taught later in the chapter.
 
  • #10
razored said:
http://texify.com/img/%5CLARGE%5C%21%5Cint_2%5E%7B%5Cinfty%7D%20%5Cfrac%7Bdx%7D%7Bx%20%5Cln%28x%29%5E%7Bp%7D%7D%20%3D%20%20%20%5Cleft%5B%20%5Cfrac%7B%20%5Cln%20%28%5Cln%28x%29%5E%7Bp%2B1%7D%29%7D%7B%28p%2B1%29%7D%20%5Cright%5D_2%5E%7B%5Cinfty%7D.gif
What do I do now?
What happens to ln(ln(x)^{p+1}) as x --> infty?

razored said:
That is taught later in the chapter.
OK, nevermind.
 
Last edited by a moderator:
  • #11
razored said:
http://texify.com/img/%5CLARGE%5C%21%5Cint_2%5E%7B%5Cinfty%7D%20%5Cfrac%7Bdx%7D%7Bx%20%5Cln%28x%29%5E%7Bp%7D%7D%20%3D%20%20%20%5Cleft%5B%20%5Cfrac%7B%20%5Cln%20%28%5Cln%28x%29%5E%7Bp%2B1%7D%29%7D%7B%28p%2B1%29%7D%20%5Cright%5D_2%5E%7B%5Cinfty%7D.gif
What do I do now?

That's not right. Substitute u=ln(x).
 
Last edited by a moderator:

1. What is the definition of convergence of a series?

The convergence of a series refers to the behavior of the terms in a sequence as the number of terms increases. If the terms get closer and closer to a finite value, the series is said to converge. If the terms do not approach a finite value, the series diverges.

2. How can I determine if a series converges or diverges?

There are several tests that can be used to determine the convergence or divergence of a series, such as the comparison test, ratio test, and integral test. These tests compare the given series to a known convergent or divergent series and use their behavior to determine the behavior of the given series.

3. What is the difference between absolute and conditional convergence?

Absolute convergence refers to a series that converges regardless of the order of the terms. On the other hand, conditional convergence refers to a series that only converges if the terms are arranged in a specific order. This means that rearranging the terms of a conditionally convergent series can result in a different sum.

4. Can a series converge to an infinite value?

No, a series can only converge to a finite value. If a series appears to be approaching an infinite value, it is actually diverging.

5. How is the convergence of a series related to the limit of its terms?

The convergence of a series is closely related to the behavior of its terms. If the limit of the terms is not equal to 0, the series will diverge. If the limit is equal to 0, further tests must be applied to determine the convergence or divergence of the series.

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