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- Thread starter gomes.
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[tex]\frac{1-\frac{1}{2r}}{1+\frac{1}{r}}\leq \frac{1}{(1+\frac{1}{r})^{3/2}}[/tex]

This is equivalent to

[tex](1-\frac{1}{2r})(1+\frac{1}{r})^{3/2}\leq 1+\frac{1}{r}[/tex]

Try to work this out. Things you could do to simplify this is squaring both terms and multiplying both sides by a suitable power of r.

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