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pmason61

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We have a process that requires 42 lbs of dry flake KOH (90% purity). Looking to find the equivalent volume (liters) of 45% liquid KOH (11.1 molar strength) - being extracted from a 55 gallon drum.

1 liter of liquid KOH has 11.1 x 56 grams/liter = 621 grams of KOH (1.37 lbs). Adjusting to 90% purity - 1.23 lbs.

So the equivalent volume of liquid KOH required would be 42/1.23 = 34 liters of 45% liquid KOH. Is this correct?