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Conversion math confusion

  1. Sep 13, 2012 #1
    1. The problem statement, all variables and given/known data

    A research submarine has a 40.0cm -diameter window 8.70cm thick. The manufacturer says the window can withstand forces up to 1.20×10^6N . What is the submarine's maximum safe depth?

    2. Relevant equations

    P= atmosheric pressure + ρg(depth)
    Pressure = Force/crossectional area

    3. The attempt at a solution

    1.2*10^6N/∏(.4/2)^2= Safe pressure
    9.55*10^6N/m^2=Psafe

    Psafe= 1atm+ρgd=101300N+1025kg/m^3*9.8m^2
    9.55*10^6kg/m^3/m^2=101300kg*m/s^2+ 1025kg/m^3*9.8m^2


    I really just don't even know how to proceed figuring out this moshpit of units or even if I'm doing this right in the first place?
     
  2. jcsd
  3. Sep 13, 2012 #2
    What's the pressure inside the submarine and what is the difference with the total water pressure?
     
  4. Sep 13, 2012 #3
    Inside the sub is 1 atm. And what do you mean? Difference between which values?
     
  5. Sep 13, 2012 #4
    If the pressure inside is equal to the pressure outside - will there be any force on the window?
     
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