# Conversion math confusion

## Homework Statement

A research submarine has a 40.0cm -diameter window 8.70cm thick. The manufacturer says the window can withstand forces up to 1.20×10^6N . What is the submarine's maximum safe depth?

## Homework Equations

P= atmosheric pressure + ρg(depth)
Pressure = Force/crossectional area

## The Attempt at a Solution

1.2*10^6N/∏(.4/2)^2= Safe pressure
9.55*10^6N/m^2=Psafe

Psafe= 1atm+ρgd=101300N+1025kg/m^3*9.8m^2
9.55*10^6kg/m^3/m^2=101300kg*m/s^2+ 1025kg/m^3*9.8m^2

I really just don't even know how to proceed figuring out this moshpit of units or even if I'm doing this right in the first place?

## Answers and Replies

Related Introductory Physics Homework Help News on Phys.org
What's the pressure inside the submarine and what is the difference with the total water pressure?

Inside the sub is 1 atm. And what do you mean? Difference between which values?

If the pressure inside is equal to the pressure outside - will there be any force on the window?