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## Homework Statement

A research submarine has a 40.0cm -diameter window 8.70cm thick. The manufacturer says the window can withstand forces up to 1.20×10^6N . What is the submarine's maximum safe depth?

## Homework Equations

P= atmosheric pressure + ρg(depth)

Pressure = Force/crossectional area

## The Attempt at a Solution

1.2*10^6N/∏(.4/2)^2= Safe pressure

9.55*10^6N/m^2=Psafe

Psafe= 1atm+ρgd=101300N+1025kg/m^3*9.8m^2

9.55*10^6kg/m^3/m^2=101300kg*m/s^2+ 1025kg/m^3*9.8m^2

I really just don't even know how to proceed figuring out this moshpit of units or even if I'm doing this right in the first place?