A research submarine has a 40.0cm -diameter window 8.70cm thick. The manufacturer says the window can withstand forces up to 1.20×10^6N . What is the submarine's maximum safe depth?
P= atmosheric pressure + ρg(depth)
Pressure = Force/crossectional area
The Attempt at a Solution
1.2*10^6N/∏(.4/2)^2= Safe pressure
I really just don't even know how to proceed figuring out this moshpit of units or even if I'm doing this right in the first place?