1. The problem statement, all variables and given/known data A research submarine has a 40.0cm -diameter window 8.70cm thick. The manufacturer says the window can withstand forces up to 1.20×10^6N . What is the submarine's maximum safe depth? 2. Relevant equations P= atmosheric pressure + ρg(depth) Pressure = Force/crossectional area 3. The attempt at a solution 1.2*10^6N/∏(.4/2)^2= Safe pressure 9.55*10^6N/m^2=Psafe Psafe= 1atm+ρgd=101300N+1025kg/m^3*9.8m^2 9.55*10^6kg/m^3/m^2=101300kg*m/s^2+ 1025kg/m^3*9.8m^2 I really just don't even know how to proceed figuring out this moshpit of units or even if I'm doing this right in the first place?