Conversion of Enthalpy (Combustion)

  • Thread starter skaboy607
  • Start date
1. The problem statement, all variables and given/known data

The enthalpy of combustion ∆Ho at t = 25 0C of Benzene (C6H6) is –3169540 kJ/kmol with the H2O in the vapour phase. Calculate the internal energy of combustion ∆Uo in kJ/kg. Calculate also ∆Ho for H2O in the liquid state.

2. Relevant equations

ΔH° = ΣΔH°f(products) - ΣΔH°f(reactants)

3. The attempt at a solution

The temperature of the reactants and products is the same so I know that I can just use the enthalpy of combustion given and then subtract the h(fg) value from steam tables to give me my answer for the liquid state. I am struggling on how to get the internal energy of combustion.

Thanks for your help.

Want to reply to this thread?

"Conversion of Enthalpy (Combustion)" You must log in or register to reply here.

Physics Forums Values

We Value Quality
• Topics based on mainstream science
• Proper English grammar and spelling
We Value Civility
• Positive and compassionate attitudes
• Patience while debating
We Value Productivity
• Disciplined to remain on-topic
• Recognition of own weaknesses
• Solo and co-op problem solving