# Conversion of Enthalpy (Combustion)

#### skaboy607

1. The problem statement, all variables and given/known data

The enthalpy of combustion ∆Ho at t = 25 0C of Benzene (C6H6) is –3169540 kJ/kmol with the H2O in the vapour phase. Calculate the internal energy of combustion ∆Uo in kJ/kg. Calculate also ∆Ho for H2O in the liquid state.

2. Relevant equations

ΔH° = ΣΔH°f(products) - ΣΔH°f(reactants)

3. The attempt at a solution

The temperature of the reactants and products is the same so I know that I can just use the enthalpy of combustion given and then subtract the h(fg) value from steam tables to give me my answer for the liquid state. I am struggling on how to get the internal energy of combustion.

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