Units of Calculation: Conversion Questions

[parcerita]

I have never been good at doing this in physics so I want to make sure I'm doping this right. The question asks:

What units would result from each of the following calculations?

a) 3cm/s x 25s
b) 4m² ÷ 6s
c) 15m/s² x 2s
d) 5m/s ÷ 3s
e) 3g ÷ 2cm³
f) 1.6kg/m² ÷ 4m

This are what I think are the answers for some:

a) cm/s²
c) m/s³

The division ones I really I'm not sure. Please help.

 

[Kurdt]

Ok with these it helps if you can turn the units into algebraic quantities and deal with them in that manner. So for part a) we have a length [L] divided by a time [T] then multiplied by a time [T]

can you simplify: $$\frac{[L]}{[T]} \times [T]$$

 

[baba89]

I appreciate your efforts to understand and ensure accuracy in your calculations. It is important to pay attention to units when performing calculations in physics, as they can greatly affect the accuracy and meaning of your results. Let's go through each calculation and determine the correct units that would result from them:

a) 3cm/s x 25s = 75cm/s^2
b) 4m^2 ÷ 6s = 0.67m^2/s
c) 15m/s^2 x 2s = 30m/s
d) 5m/s ÷ 3s = 1.67m/s^2
e) 3g ÷ 2cm^3 = 1.5g/cm^3
f) 1.6kg/m^2 ÷ 4m = 0.4kg/m

In order to determine the units, we must first look at the units of each individual value in the calculation. For example, in the first calculation (a), we have cm/s x s. The unit for speed is cm/s, and the unit for time is s. When multiplying, we multiply the numbers and also the units, so we end up with (cm/s) x s = (cm/s) x (s) = cm/s^2. Similarly, in the fifth calculation (e), we have g ÷ cm^3. The unit for mass is g and the unit for volume is cm^3. When dividing, we divide the numbers and also the units, so we end up with (g) ÷ (cm^3) = g/cm^3.

I hope this helps clarify the units for each calculation. Remember to always pay attention to units and double check your calculations to ensure accuracy. If you are still unsure, it is always helpful to consult with a teacher or another scientist for guidance. Keep up the good work!