- #1
sfunds
- 3
- 0
Conversion to cylindrical co-ordinates...please help
I came a across the following problem in William Hayt book.
1.) Expresss in cylindrical componenets:(a) vector from C ( 3,2,-7) to D (-1,-4,2)
The following is the solution in the solution manual of that book:
a) the vector from C(3, 2,−7) to D(−1,−4, 2):
C(3, 2,−7) → C(ρ = 3.61, φ = 33.7◦, z = −7) and
D(−1,−4, 2) → D(ρ = 4.12, φ = −104.0◦, z = 2).
Now RCD = (−4,−6, 9) and Rρ = RCD · aρ = −4 cos(33.7) − 6 sin(33.7) = −6.66. Then
Rφ = RCD · aφ = 4 sin(33.7) − 6 cos(33.7) = −2.77. So RCD = −6.66aρ − 2.77aφ + 9az
why have they taken angle 33.7 to find RCD ??
I don't understand
I came a across the following problem in William Hayt book.
1.) Expresss in cylindrical componenets:(a) vector from C ( 3,2,-7) to D (-1,-4,2)
The following is the solution in the solution manual of that book:
a) the vector from C(3, 2,−7) to D(−1,−4, 2):
C(3, 2,−7) → C(ρ = 3.61, φ = 33.7◦, z = −7) and
D(−1,−4, 2) → D(ρ = 4.12, φ = −104.0◦, z = 2).
Now RCD = (−4,−6, 9) and Rρ = RCD · aρ = −4 cos(33.7) − 6 sin(33.7) = −6.66. Then
Rφ = RCD · aφ = 4 sin(33.7) − 6 cos(33.7) = −2.77. So RCD = −6.66aρ − 2.77aφ + 9az
why have they taken angle 33.7 to find RCD ??
I don't understand
Last edited: