# Convert to Log Function

1. Oct 25, 2007

### shoook

1. Convert to logarithmic function: e^3=0.0498

3. ln(-3)=0.0166 is my guess

2. Oct 25, 2007

### rocomath

you cannot take the ln of a negative number

3. Oct 25, 2007

### shoook

okay well I was wrong, could it be ln(3)=0.0166?

4. Oct 25, 2007

### rocomath

where is .01666 coming from?

5. Oct 25, 2007

### shoook

i divided 0.0498 by 3. that is totally wrong though.

6. Oct 25, 2007

### rocomath

yes.

since it just asks you to convert to log form, just leave it

$$e^{3}=0.0498$$

$$ln(e^{3})=ln(0.0498)$$

7. Oct 25, 2007

### shoook

okay if the equation was e^-3=0.0498 would I just rewrite it as:
ln(e^-3)=ln(0.0498) ? Also, does ln remain on the right side as well as the left?

8. Oct 25, 2007

### rocomath

no they cancel each other out, i was just showing you the operation; sorry for the confusion.

$$3=ln(0.0498)$$

Last edited: Oct 25, 2007
9. Oct 25, 2007

### Dick

Uh, you mean -3=ln(0.0498...), right?

10. Oct 25, 2007

### rocomath

then it would be

$$-3=ln(0.0498)$$

11. Oct 25, 2007

### rocomath

that's his 2nd question

12. Oct 25, 2007

### Dick

Well, ok, however you want to handle it. But seeing stuff like 3=ln(0.0498) makes me nervous.

13. Oct 25, 2007

lol sorry!