1. Sep 27, 2005 #1

   Bob19

   

   Hi
   
   If I have the following equation:
   
   x^2 - 2y = 0
   
   I need to convert it into polar coordinants:
   
   r^2 * cos(phi)^2 - 2*r* sin(phi) = 0
   
   Is this correct ?
   
   /Bob

    

   Bob19, Sep 27, 2005
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3. Sep 27, 2005 #2

   arildno

   

   Science Advisor

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   Yes, it is correct.

    

   arildno, Sep 27, 2005
4. Sep 27, 2005 #3

   HallsofIvy

   

   Science Advisor

   And, of course, as long as r is not 0, you can divide through by r to get
   [tex]r cos^2(\theta)- 2sin(\theta)= 0[/tex]
   or
   [tex]r= \frac{2sin(\theta)}{cos^2(\theta)}[/tex]
   
   (It is customary to use "theta" in polar coordinates rather than "phi")

    

   HallsofIvy, Sep 27, 2005

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