Converting from square to polar coordinants

  • Thread starter Bob19
  • Start date
  • #1
Bob19
71
0
Hi

If I have the following equation:

x^2 - 2y = 0

I need to convert it into polar coordinants:

r^2 * cos(phi)^2 - 2*r* sin(phi) = 0

Is this correct ?

/Bob
 

Answers and Replies

  • #2
arildno
Science Advisor
Homework Helper
Gold Member
Dearly Missed
10,089
135
Yes, it is correct.
 
  • #3
HallsofIvy
Science Advisor
Homework Helper
43,021
971
Bob19 said:
Hi

If I have the following equation:

x^2 - 2y = 0

I need to convert it into polar coordinants:

r^2 * cos(phi)^2 - 2*r* sin(phi) = 0

Is this correct ?

/Bob

And, of course, as long as r is not 0, you can divide through by r to get
[tex]r cos^2(\theta)- 2sin(\theta)= 0[/tex]
or
[tex]r= \frac{2sin(\theta)}{cos^2(\theta)}[/tex]

(It is customary to use "theta" in polar coordinates rather than "phi")
 

Suggested for: Converting from square to polar coordinants

Replies
10
Views
460
Replies
24
Views
227
Replies
4
Views
770
  • Last Post
Replies
7
Views
999
  • Last Post
Replies
16
Views
548
Replies
20
Views
2K
  • Last Post
Replies
4
Views
543
Replies
13
Views
667
Top