# Converting into polar integrals from rectangular

1. Apr 13, 2005

### VinnyCee

Here is the problem:

Convert $$\int_{-1}^{1}\int_{-\sqrt{1 - y^2}}^{\sqrt{1 - y^2}}\;\ln\left(x^2\;+\;y^2\;+\;1\right)\;dx\;dy$$ into polar coordinates.

Here is what I have:

$$\int_{0}^{2\pi}\int_{0}^{1}\;r\;\ln\left(r^2\;+\;1\right)\;dr\;d\theta$$

Is that the correct conversion? I could list all of the steps that I did to get to that answer, but that would take forever! Can someone check please?

2. Apr 13, 2005

### Oggy

That's correct.