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## Homework Statement

Convert 4.18 joules/(grams * Kelvin) to calories/(pound * Farenheit)

(heat)

## Homework Equations

1 Kelvin = -272 Celcius

1 Calorie = 4.18 Joules

1 Celcius = 33.8 Fahrenheit

1 lb. = 454 grams

## The Attempt at a Solution

[itex]\frac{4.18 Joules}{1 gram \cdot 1 Kelvin} \cdot \frac{-272 Kelvin}{1 Celcius} \cdot \frac{1 Celcius}{33.8 Fahrenheit} \cdot \frac{1 Calorie}{4.18 Joules} \cdot \frac{4.54 grams}{1 pound} \\\\

\frac{-272 \cdot 4.54 calories}{33.8 lb. \cdot Fahrenheit} \\\\

\frac{-36.5349 calories}{lb. \cdot Fahrenheit}[/itex]

But the solution is 252 cal/(lb. * fahrenheit). What did I do incorrectly?