Converting m/s to Newtons

  • Thread starter ryanking93
  • Start date
  • #1
ryanking93
4
1
Homework Statement:
Add the following vectors and determine the resultants (length, angle from O)
Relevant Equations:
3 m/s. 45° + 5 m/s. 135°
So I've charted the equation above, and received the correct resultant 104.0° I used a scale of 1m/s = 2cm and I get 11.8cm which gives me 23.6m/s but when I look at the answer it is 104.0° / 5.83N

I have no idea why its in Newtons.
 

Answers and Replies

  • #2
Lnewqban
Homework Helper
Gold Member
2,618
1,419
Welcome! :smile:
Could you post the original text of the problem?
The value you found is not correct.
 
  • #3
ryanking93
4
1
Welcome! :smile:
Could you post the original text of the problem?

Thank you. I have attached both the questions and answers I am referencing. The specific question is "C"

And my answer to the question.
 

Attachments

  • IMG_5845.jpeg
    IMG_5845.jpeg
    35.9 KB · Views: 79
  • IMG_5846.jpeg
    IMG_5846.jpeg
    51.3 KB · Views: 81
  • IMG_5847.jpeg
    IMG_5847.jpeg
    65.7 KB · Views: 72
  • #4
OmCheeto
Gold Member
2,265
2,740
Typographical error.
 
  • #5
ryanking93
4
1
Typographical error.

Okay, Thank you. I thought I might be losing it for a minute.
 
  • #6
Lnewqban
Homework Helper
Gold Member
2,618
1,419
Thank you. I have attached both the questions and answers I am referencing. The specific question is "C"

And my answer to the question.
It is an error of the booklet, the resultant vector should be in m/s.
Note that the angle between your vectors is 90°, therefore, you could apply the Pythagorean equation and see that the result can't be 23.6 m/s.
 
  • #7
ryanking93
4
1
It is an error of the booklet, the resultant vector should be in m/s.
Note that the angle between your vectors is 90°, therefore, you could apply the Pythagorean equation and see that the result can't be 23.6 m/s.

Ahhhh I see now! My issue was when I ended up with 11.8cm instead of dividing by 2 I multiplied by 2. As my scale was 1m/s = 2cm. I end up with 5.9m/s.

Thanks a million for the help!
 
  • #8
Lnewqban
Homework Helper
Gold Member
2,618
1,419
Ahhhh I see now! My issue was when I ended up with 11.8cm instead of dividing by 2 I multiplied by 2. As my scale was 1m/s = 2cm. I end up with 5.9m/s.

Thanks a million for the help!
When adding vectors, it is good to check that the result is not greater than the addition of the magnitude of each independent vector.
You are welcome. :smile:
 

Suggested for: Converting m/s to Newtons

Replies
10
Views
456
Replies
20
Views
314
Replies
10
Views
450
  • Last Post
Replies
5
Views
4K
  • Last Post
Replies
8
Views
1K
  • Last Post
Replies
7
Views
343
Replies
12
Views
2K
Top