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Converting ppm to mg/L

  1. Nov 14, 2011 #1
    1. The problem statement, all variables and given/known data
    A is a stable powder
    B is water
    C is the product of the powder being in contact with water.

    A is soluble in substance B and for every gram of A 10% is C.

    For a concentration of 0.5ppm of C in twenty liters of water how many grams of A do you need?


    3. The attempt at a solution
    I went on the assumption that ppm=mg/l.
    So 0.5ppm=0.5mg/l, and I would need 10mg for the twenty liters
    Which means that I would need 100mg of A.

    Is this correct?
    1. The problem statement, all variables and given/known data



    2. Relevant equations



    3. The attempt at a solution
     
  2. jcsd
  3. Nov 14, 2011 #2

    Borek

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    Staff: Mentor

    That would be my answer as well, although I find the wording of the question confusing.
     
  4. Nov 14, 2011 #3
    Thanks for the confirmation, I'm just replying to say that 100mg was indeed the correct answer.

    If you don't mind me asking, how did the wording confuse you?
     
  5. Nov 14, 2011 #4

    Borek

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    Staff: Mentor

    If 0.1g of A reacted with water, what is mass of the product? Again 0.1g? Not impossible, but counterintuitive, at least to me.
     
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