Converting Problems: Get Help with Formula Steps

  • Thread starter nutsy76
  • Start date
In summary, the conversation is about the process of converting units using conversion factors. The speaker is struggling to understand the steps to take after knowing the formula to use. They are working on a problem involving a Grand Prix racer completing a 500 km race in 2 hours and 15 minutes and need to find the average speed in km/hr and m/s. The speaker offers an example of how to convert units using a series of multiplications by factors equal to one. They suggest converting the time to either hours or minutes before solving the problem.
  • #1
nutsy76
1
0
I am having problems on conversion factors. I don't even know where to begin with my problems. I know which formulas to use I just don't know what to do after that. For ex I am working on this prob:

A Grand Prix racer completes a 500 km race in 2hr 15min. What is the average speed of the car in km per hr and meters per sec?

Like I said I know what formula to use but what are the steps to convert? I keep getting stuck on how to start.

Thanks.
 
Physics news on Phys.org
  • #2
nutsy76 said:
I am having problems on conversion factors. I don't even know where to begin with my problems. I know which formulas to use I just don't know what to do after that. For ex I am working on this prob:

A Grand Prix racer completes a 500 km race in 2hr 15min. What is the average speed of the car in km per hr and meters per sec?

Like I said I know what formula to use but what are the steps to convert? I keep getting stuck on how to start.

Thanks.

All conversions should be thought of as a series of multiplications by factors equal to one. Here is an example I recently did

[tex]a = \frac{{45\frac{{mi}}{h}}}{{1s}} = \frac{{45mi}}{{hs}}\left( {\frac{{5280ft}}{{mi}}} \right)\left( {\frac{{12in}}{{ft}}} \right)\left( {\frac{{2.54cm}}{{in}}} \right)\left( {\frac{{1m}}{{100cm}}} \right)\left( {\frac{1 h}{{60\min }}} \right)\left( {\frac{{1\min }}{{60{\mathop{\rm s}\nolimits} }}} \right) = 20.1\frac{m}{{s^2 }}[/tex]

Every term in parentheses is equal to one because the numerator is equal to the denominator. It is simply a matter of choosing to write the fractions in such a way that units you want to replace divide out and the units you want to convert to are left. See if you can follow this model and do your problem.

You will have to express your time either in hours or in minutes by doing a prliminary conversion of one of those and adding them together.
 
Last edited:
  • #3


Hello there,

It seems like you are having some trouble with converting problems and are unsure of the steps to take after identifying the formula to use. Don't worry, you are not alone! Many students struggle with conversions and it can be a bit overwhelming at first. However, with some practice and guidance, you can become confident in solving these types of problems.

Firstly, it's important to understand the concept of conversion factors. These are ratios that allow us to convert between different units of measurement. For example, 1 km = 1000 meters. This means that if we want to convert from km to meters, we can multiply the given value in km by 1000 to get the equivalent value in meters.

Now, let's apply this concept to the problem you mentioned. We are given the distance of 500 km and the time of 2 hours and 15 minutes (which can be written as 2.25 hours). To find the average speed, we use the formula: speed = distance/time. So, we have:

Speed = 500 km / 2.25 hours

To convert hours to seconds, we can use the conversion factor 1 hour = 3600 seconds. So, we multiply the given time of 2.25 hours by 3600 to get the equivalent value in seconds:

2.25 hours * 3600 seconds/hour = 8100 seconds

Now, we can plug in the converted time value into our formula:

Speed = 500 km / 8100 seconds

To convert km to meters, we use the conversion factor 1 km = 1000 meters. So, we multiply the given distance of 500 km by 1000 to get the equivalent value in meters:

500 km * 1000 meters/km = 500,000 meters

Now, we can plug in the converted distance value into our formula:

Speed = 500,000 meters / 8100 seconds

To simplify this, we can divide both the numerator and denominator by 100 to get the speed in meters per second:

Speed = 5000 meters / 81 seconds = 61.73 meters/second

To convert this to kilometers per hour, we can use the conversion factor 1 meter/second = 3.6 kilometers/hour. So, we multiply the speed in meters/second by 3.6 to get the equivalent value in kilometers/hour:

61.73 meters/second
 

1. What is the purpose of converting problems in science?

Converting problems in science is important because it allows us to accurately and efficiently solve complex equations and formulas, making it easier to understand and analyze data. It also helps us to make comparisons and predictions based on the relationships between different units of measurement.

2. What are the steps involved in converting problems?

The steps for converting problems vary depending on the type of problem and units involved, but generally include identifying the given and desired units, determining the conversion factor, setting up the equation using the conversion factor, and canceling out units until the desired unit remains.

3. How do I know which conversion factor to use?

The conversion factor to use can be determined by understanding the relationship between the given and desired units. This can be done by referring to conversion tables, using dimensional analysis, or using the conversion factor given in the problem.

4. What are some common mistakes to avoid when converting problems?

Some common mistakes when converting problems include using the wrong conversion factor, not properly canceling out units, forgetting to include a unit in the final answer, and not paying attention to significant figures.

5. Can I use the internet to help me with converting problems?

Yes, there are many online resources available to help with converting problems, including conversion calculators, tutorials, and practice problems. However, it is important to double check the accuracy of the information and to understand the steps involved in converting problems for better comprehension and problem-solving skills.

Similar threads

Replies
10
Views
466
  • Introductory Physics Homework Help
Replies
3
Views
187
  • Introductory Physics Homework Help
Replies
3
Views
3K
  • Introductory Physics Homework Help
Replies
3
Views
235
  • Introductory Physics Homework Help
Replies
6
Views
5K
  • Introductory Physics Homework Help
Replies
1
Views
2K
  • Introductory Physics Homework Help
Replies
14
Views
1K
  • Introductory Physics Homework Help
Replies
11
Views
2K
  • Introductory Physics Homework Help
Replies
5
Views
368
  • Introductory Physics Homework Help
Replies
22
Views
1K
Back
Top