- #1

StarkyDee

So I graphed the points and got the hypotenuse, r = 8.

How do I convert 4[itex]\sqrt{3}}[/itex]) to degrees?

(4[itex]\sqrt{3}}[/itex]) = 6.92820 Is this in radians?

and do I then multiply it by (180/pi) to get degrees?

thanks.

- Thread starter StarkyDee
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- #1

StarkyDee

So I graphed the points and got the hypotenuse, r = 8.

How do I convert 4[itex]\sqrt{3}}[/itex]) to degrees?

(4[itex]\sqrt{3}}[/itex]) = 6.92820 Is this in radians?

and do I then multiply it by (180/pi) to get degrees?

thanks.

- #2

Hurkyl

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[itex]4 \sqrt{3}[/itex] isn't an angle...

- #3

chroot

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Why are you trying to convert the cartesian y-coordinate to degrees? That doesn't even make sense.

- Warren

- #4

StarkyDee

Ah. Inverse Tan of y/x.

4[itex]\sqrt{3}}[/itex]/-4 = -1.7320 = -60 degrees.

Thanks ~Dave~

4[itex]\sqrt{3}}[/itex]/-4 = -1.7320 = -60 degrees.

Thanks ~Dave~

- #5

Hurkyl

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Don't forget to check that your answer is in the correct quadrant!

- #6

StarkyDee

but when i graph (-4,4[itex]\sqrt{3}}[/itex]) it is only valid in the 2nd quadrant and you can't have a -60 degrees in the 2nd quad. so if i start in the 4 quadrant at -60

the 3 points would be: (8,-60);

add 360 (8,-240);

opposite angle (8,120). is this correct?

thanks again!

- #7

Hurkyl

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All of your answers

- #8

StarkyDee

but (8,-240) and (8,120) and (8,-600) would be in the 2nd quadrant.

- #9

Hurkyl

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right.

- #10

StarkyDee

Studying for finals have turned my brain into mush.

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