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Converting to kg ? simple question

  1. Feb 8, 2010 #1
    1. The problem statement, all variables and given/known data
    how do i convert 938.3MeV/(c^2) to kilo grams
    3. The attempt at a solution

    so this is mega electron volts divided by c^2 do i just divide it by 1.602*10^(-19) joules
    is e measured in coulombs and a volt is a joule per coulomb.
     
  2. jcsd
  3. Feb 8, 2010 #2
    The eV is a measure of energy, equalling somewhere about 1.6 * 10^(-19) J
    1 J = 1 kg * m^2/s^2
    I assume c wants to be the speed of the light, which is given in m/s

    so 1 eV/c^2= (some scalar) * kg * m^2/s^2 / (m/s)^2
    now what you get by simplifying?

    It always helps not to forget to write the units, and go for base units when in doubt.
     
  4. Feb 8, 2010 #3
    thanks , ok i see , so i multiply it by 1.602*10^(-19)J/1eV to get it Kg .
    correct
     
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