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Convex mirror reflection

  • #1

Homework Statement



For self study, I've been trying to understand my convex mirror.
Some online instruction I've been following states that if an incidence ray (red line in my model, below) parallel to the principal axis (black line) hits a convex mirror (full curvature outlined in black, centre C), the reflected ray (purple) extended back passes through the focal point (F).

Homework Equations


In my graphed model below, the points & vectors are
centre of curvature, C is at origin
focal point, F = (25,0)
normal to incident, N = (0.91128...,-0.41178...)
incident, I = (-1,0)
reflected, R = (0.66087...,-0.75049...)

The Attempt at a Solution



wtf.png

I graphed my model (above) but the reflected vector does not run exactly through my focal point as expected. I've checked this is not simply a rounding error (or any other obvious mistakes). There are also other problems when I plot more incident vectors emanating from the same point (not shown): the reflected vectors do not converge on a virtual image point as expected. Something crucial is missing from my understanding of this problem.
 

Answers and Replies

  • #2
rl.bhat
Homework Helper
4,433
5
In the concave mirror, the reflected ray will pass through F if the ray is parallel to the principle and close to the principle axis. Such rays are called par axial rays.
 
  • #3
Are you just saying the principle is an approximation. I.e. in fact it never passes exactly through F at all (except of course when the incident ray is along the principal axis), but the reflected ray gets very close to F when the incident is close to the principal axis
 
  • #4
rl.bhat
Homework Helper
4,433
5
Yes.
 

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