- #1
whitehorsey
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1. Shiny lawn spheres placed on pedestals are convex mirrors. One such sphere has a diameter of 40 cm. A 12 cm robin sits in a tree 1.5 m from the sphere.
a) Where is the image of the robin?
b) How long is the robin's image?
2. 1/f = 1/do + 1/di
3. a. 1/f = 1/do + 1/di
di = dof/1/f = do - f
= 150(10)/ 150 -10
= 10.71 cm
b. m = hi/ho = di/do
hi = ho (di/do)
= 12(-10.71/150)
= -0.857 cm
I'm not sure if this is right.
a) Where is the image of the robin?
b) How long is the robin's image?
2. 1/f = 1/do + 1/di
3. a. 1/f = 1/do + 1/di
di = dof/1/f = do - f
= 150(10)/ 150 -10
= 10.71 cm
b. m = hi/ho = di/do
hi = ho (di/do)
= 12(-10.71/150)
= -0.857 cm
I'm not sure if this is right.